metal oxides
•
Weigh a sample of metal
in a crucible
•
Heat is
strongly so it oxidises. Have a lid
on the crucible, but briefly lift it periodically to let in air.
•
Weigh it again. It should be heavier.
•
The increase
in mass is the mass of oxygen that has added to the metal.
•
Work out the moles of the metal and the
oxygen to deduce the formula
(see Section 1.25)
water
•
Electrolyse a
sample of water (acidified to increase
conductivity) in a Hoffmann Voltameter (below).
•
Measure the volume
of hydrogen and oxygen produced at each electrode
•
Since one mole of any gas occupies the same volume, the ratio of the two volumes is the same as the mole
ratio, which should be 2H : 1O. This gives the formula H2O.
water of crystallisation
•
Weigh a sample of the hydrated salt
•
Heat the salt in
a crucible to drive off the water
until there is no further change in mass
•
Record the final mass and subtract it from the initial mass.
This gives the mass of
water.
•
Work out the moles of the anhydrous salt (final mass) and the moles of the water
(the drop in mass).
The ratio of these moles gives the formula of the hydrated salt.
e.g. 2.50 g of hydrated
copper sulphate is heated strongly
until there is no further
change in mass, The final mass is 1.60 g. What is the
formula of the hydrated salt?
moles of anhydrous CuSO4 = 1.60 g
÷ (64 + 32 + 4x16) = 0.010
mol
moles of water =
(2.50 - 1.60) g ÷ (16
+ 2x1) = 0.050 mol
ratio water : CuSO4 = 0.050 ÷ 0.010 = 5
: 1
therefore hydrated salt formula = CuSO4.5H2O
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